-1=2/3*3^(3x+12)

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Solution for -1=2/3*3^(3x+12) equation: 



-1=2/3*3^(3x+12)

We move all terms to the left:

-1-(2/3*3^(3x+12))=0



Domain of the equation: 3*3^(3x+12))!=0

x∈R



We multiply all the terms by the denominator


-(2-1*3*3^(3x+12))=0



We calculate terms in parentheses: -(2-1*3*3^(3x+12)), so:

2-1*3*3^(3x+12)

determiningTheFunctionDomain
-1*3*3^(3x+12)+2

Wy multiply elements

-9x*3+2

Wy multiply elements

-27x+2

Back to the equation:

-(-27x+2)



We get rid of parentheses

27x-2=0

We move all terms containing x to the left, all other terms to the right

27x=2

x=2/27

x=2/27

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